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Proof step 54 from proof bytes2bytes-zero (previous step)

b2i(by) = 0, b2i(by0) < 0, ∀ by0, by, bytes1. # bytes1 < #(bytes0 + by1 ') → b2i(by) = 0 ∧ b2i(by0) < 0 → bits2bytes(sgn(byte2bits(by) + byte2bits(by0) + bytes2bits(bytes1))) = by ' + by0 ' + bytes1 ⊦ bits2bytes(sgn((byte2bits(by) + byte2bits(by0) + bytes2bits(bytes0)) + byte2bits(by1))) = by ' + by0 ' + bytes0 + by1 '

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ true ∈ bits ∧ false ∈ bits → sgn(bits + bits0) = sgn(bits) + bits0 subst: [bits0, bits] → [byte2bits(by1), byte2bits(by) + byte2bits(by0) + bytes2bits(bytes0)] rotate: F spec: bitopsaux inst: name: sgn-append-01

Additional information

Used terms: byte2bits(by1), byte2bits(by) + byte2bits(by0) + bytes2bits(bytes0)