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Proof step 56 from proof bytes2bytes-zero (previous step)

¬(true ∈ byte2bits(by) + byte2bits(by0) + bytes2bits(bytes0) ∧ false ∈ byte2bits(by) + byte2bits(by0) + bytes2bits(bytes0)), b2i(by) = 0, b2i(by0) < 0, ∀ by0, by, bytes1. # bytes1 < #(bytes0 + by1 ') → b2i(by) = 0 ∧ b2i(by0) < 0 → bits2bytes(sgn(byte2bits(by) + byte2bits(by0) + bytes2bits(bytes1))) = by ' + by0 ' + bytes1 ⊦ bits2bytes(sgn((byte2bits(by) + byte2bits(by0) + bytes2bits(bytes0)) + byte2bits(by1))) = by ' + by0 ' + bytes0 + by1 '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 57:
b2i(by) = 0, b2i(by0) < 0, ∀ by0, by, bytes1. # bytes1 < #(bytes0 + by1 ') → b2i(by) = 0 ∧ b2i(by0) < 0 → bits2bytes(sgn(byte2bits(by) + byte2bits(by0) + bytes2bits(bytes1))) = by ' + by0 ' + bytes1 ⊦ bits2bytes(sgn((byte2bits(by) + byte2bits(by0) + bytes2bits(bytes0)) + byte2bits(by1))) = by ' + by0 ' + bytes0 + by1 ', (true ∈ byte2bits(by) ∨ true ∈ byte2bits(by0) ∨ true ∈ bytes2bits(bytes0)) ∧ (false ∈ byte2bits(by) ∨ false ∈ byte2bits(by0) ∨ false ∈ bytes2bits(bytes0))

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ∈ bits + bits0 ↔ ¬ ¬(boolvar ∈ bits ∨ boolvar ∈ bits0);