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Proof step 11 from proof bytes2int-100x (previous step)

i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m) ≠ [], bytes2int(i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m)) = 2 ^ (8 * (1 + n→i(m)) - 1) ⊦ bytes2int(i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m)) * 256 + band(b2i(i2b(0)), 255) = 2 ^ (8 * (2 + n→i(m)) - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
bytes2int(i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m)) = 2 ^ (8 * (1 + n→i(m)) - 1) ⊦ 2 ^ (8 * (1 + n→i(m)) - 1) * 256 = 2 ^ (8 * (2 + n→i(m)) - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ by ' + bytes ≠ [];% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + 0 = i;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ band(i, j) = band(j, i);% ⊦ band(i, band(i0, j)) = band(band(i, i0), j);% ⊦ 0 ≤ i → band(i, 255) = i % 256;% ⊦ b2i(i2b(0)) = 0;