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Proof step 9 from proof bytes2int-100x (previous step)

bytes2int(i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m)) = 2 ^ (8 * (1 + n→i(m)) - 1) ⊦ bytes2int(i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m) + i2b(0) ') = 2 ^ (8 * (2 + n→i(m)) - 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ bytes ≠ [] → bytes2int(bytes + by ') = bytes2int(bytes) * 256 + band(b2i(by), 255)
Proof step 11:
i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m) ≠ [], bytes2int(i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m)) = 2 ^ (8 * (1 + n→i(m)) - 1) ⊦ bytes2int(i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m)) * 256 + band(b2i(i2b(0)), 255) = 2 ^ (8 * (2 + n→i(m)) - 1)

Rule argument

name: bytes2int-rec rotate: F subst: [by, bytes] → [i2b(0), i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m)]

Additional information

Used simplifier rules: ⊦ ¬ bytes + bytes0 ≠ [] ↔ bytes = [] ∧ bytes0 = [];% ⊦ by ' ≠ [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1; Used terms: i2b(0), i2b(0) ' + i2b(~128) ' + mklist(i2b(0), m)