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Proof step 3 from proof bytes2int-diff (previous step)

# bytes0 = # bytes ∧ bytes2int(bytes0) = bytes2int(bytes), ∀ bytes0, bytes1. # bytes1 < # bytes → # bytes0 = # bytes1 ∧ bytes2int(bytes0) = bytes2int(bytes1) → bytes0 = bytes1 ⊦ bytes0 = bytes

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
bytes2int(bytes0) = bytes2int(bytes), # bytes0 = # bytes, ∀ bytes0, bytes1. # bytes1 < # bytes → # bytes0 = # bytes1 ∧ bytes2int(bytes0) = bytes2int(bytes1) → bytes0 = bytes1 ⊦ bytes0 = bytes

Proof step 3 from proof bytes2int-diff (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information