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Proof step 4 from proof bytes2int-diff (previous step)

bytes2int(bytes0) = bytes2int(bytes), # bytes0 = # bytes, ∀ bytes0, bytes1. # bytes1 < # bytes → # bytes0 = # bytes1 ∧ bytes2int(bytes0) = bytes2int(bytes1) → bytes0 = bytes1 ⊦ bytes0 = bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ 1 < # bytes → bytes2int(bytes) = bytes2int(bytes.butlast) * 256 + band(b2i(bytes.last), 255)
Proof step 6:
¬ 1 < # bytes, bytes2int(bytes0) = bytes2int(bytes), # bytes0 = # bytes, ∀ bytes0, bytes1. # bytes1 < # bytes → # bytes0 = # bytes1 ∧ bytes2int(bytes0) = bytes2int(bytes1) → bytes0 = bytes1 ⊦ bytes0 = bytes
Proof step 16:
1 < # bytes, bytes2int(bytes0) = bytes2int(bytes.butlast) * 256 + band(b2i(bytes.last), 255), # bytes0 = # bytes, ∀ bytes0, bytes1. # bytes1 < # bytes → # bytes0 = # bytes1 ∧ bytes2int(bytes0) = bytes2int(bytes1) → bytes0 = bytes1 ⊦ bytes0 = bytes

Rule argument

name: bytes2int-rec-01 rotate: F subst: [bytes] → [bytes]

Additional information

Used terms: bytes