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Proof step 15 from proof bytes2int-fillsgn-zero (previous step)

∀ by. by ∈ bytes → b2i(by) = 0 ⊦ bytes = [], mklist(i2b(0), # bytes - 1) + i2b(0) ' = bytes, # bytes = 1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 16:
# bytes = m + 1 ∧ # bytes ≠ 0, ∀ by. by ∈ bytes → b2i(by) = 0 ⊦ bytes = [], mklist(i2b(0), m) + i2b(0) ' = bytes, # bytes = 1

Rule argument

seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [# bytes, m] rotate: T spec: nat inst: name: elim-pred-c

Additional information

Used simplifier rules: ⊦ # bytes = 0 ↔ bytes = [];%n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: # bytes, m