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Proof step 16 from proof bytes2int-fillsgn-zero (previous step)

# bytes = m + 1 ∧ # bytes ≠ 0, ∀ by. by ∈ bytes → b2i(by) = 0 ⊦ bytes = [], mklist(i2b(0), m) + i2b(0) ' = bytes, # bytes = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
# bytes = m + 1, ∀ by. by ∈ bytes → b2i(by) = 0 ⊦ mklist(i2b(0), m) + i2b(0) ' = bytes, bytes = [], m = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1;% ⊦ # bytes = 0 ↔ bytes = [];