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Proof step 17 from proof bytes2int-len-one-01 (previous step)

0 ≤ band(b2i(by), 255), band(b2i(by), 255) < 128 ⊦ bytes0 = [], bytes0.first = i2b(0), true ∈ bytes2bits(bytes0)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 ≤ b2i(by) → band(b2i(by), 255) = b2i(by) subst: [by] → [by] rotate: F spec: byte inst: name: byte-011x-pos

Additional information

Used simplifier rules: ⊦ band(i, j) = band(j, i);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < 0 → band(i, 255) = (i + 1) % 256 + 255;% ⊦ (b2i(by) + 1) % 256 = b2i(by) + 1;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ band(i, band(i0, j)) = band(band(i, i0), j);% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ ¬ b2i(by) < ~128; Used terms: by