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Proof step 19 from proof bytes2int-len-one-01 (previous step)

0 ≤ b2i(by), 0 ≤ b2i(by), b2i(by) < 128 ⊦ bytes0 = [], bytes0.first = i2b(0), true ∈ bytes2bits(bytes0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
b2i(by) < 128, 0 ≤ b2i(by) ⊦ bytes0 = [], bytes0.first = i2b(0), true ∈ bytes2bits(bytes0)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)