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Proof step 14 from proof bytes2int-len-one-02 (previous step)

bytes = bytes0 + by0 ', 0 ≤ band(255, b2i(by0)) + 256 * bytes2int((i2b(0) ' + by ') + bytes0), band(255, b2i(by0)) + 256 * bytes2int((i2b(0) ' + by ') + bytes0) < 128, b2i(by) < 0 ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i + j = j + i;% ⊦ i * j = j * i;% ⊦ band(i, j) = band(j, i);% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + by ' ≠ [];