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Proof step 15 from proof bytes2int-len-one-02 (previous step)

0 ≤ band(255, b2i(by0)) + 256 * bytes2int((i2b(0) ' + by ') + bytes0), b2i(by) < 0, band(255, b2i(by0)) + 256 * bytes2int((i2b(0) ' + by ') + bytes0) < 128 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 16:
256 * bytes2int((i2b(0) ' + by ') + bytes0) < 128, 0 ≤ band(255, b2i(by0)) + 256 * bytes2int((i2b(0) ' + by ') + bytes0), b2i(by) < 0, band(255, b2i(by0)) + 256 * bytes2int((i2b(0) ' + by ') + bytes0) < 128 ⊦
Proof step 19:
0 ≤ band(255, b2i(by0)) + 256 * bytes2int((i2b(0) ' + by ') + bytes0), b2i(by) < 0, band(255, b2i(by0)) + 256 * bytes2int((i2b(0) ' + by ') + bytes0) < 128 ⊦ 256 * bytes2int((i2b(0) ' + by ') + bytes0) < 128

Rule argument

fma: 256 * bytes2int((i2b(0) ' + by ') + bytes0) < 128

Additional information

Used formulas: 256 * bytes2int((i2b(0) ' + by ') + bytes0) < 128