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Proof step 10 from proof bytes2int-zero-04 (previous step)

0 ≤ b2i(by) ⊦ bits2int(mklist(false, 8) + byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
0 ≤ b2i(by) ⊦ bits2uint(byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

Rule argument

Additional information

Used simplifier rules: ⊦ bits2uint(false ' + bits) = bits2uint(bits);% ⊦ bits2int(false ' + bits) = bits2uint(bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;% ⊦ mklist(boolvar, 0) = [];%n ≠ 0 ⊦ mklist(false, (* n)) = false ' + mklist(false, n -1);