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Proof step 11 from proof bytes2int-zero-04 (previous step)

0 ≤ b2i(by) ⊦ bits2uint(byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits)
Proof step 13:
¬(¬ (byte2bits(by) + bytes2bits(bytes)).first ∧ byte2bits(by) + bytes2bits(bytes) ≠ []), 0 ≤ b2i(by) ⊦ bits2uint(byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

Rule argument

seq: ⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits) subst: [bits] → [byte2bits(by) + bytes2bits(bytes)] rotate: F spec: int2bits inst: name: bits2int-pos-02

Additional information

Used terms: byte2bits(by) + bytes2bits(bytes)