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Proof step 13 from proof bytes2int-zero-04 (previous step)

¬(¬ (byte2bits(by) + bytes2bits(bytes)).first ∧ byte2bits(by) + bytes2bits(bytes) ≠ []), 0 ≤ b2i(by) ⊦ bits2uint(byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
0 ≤ b2i(by), (byte2bits(by) + bytes2bits(bytes)).first ⊦ bits2uint(byte2bits(by) + bytes2bits(bytes)) = bits2int(byte2bits(by) + bytes2bits(bytes))

Rule argument

Additional information

Used simplifier rules: byte2bits-empty: ⊦ byte2bits(by) ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];