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Proof step 1 from proof bytes2int-zero-05 (conclusion)

⊦ 0 ≤ n ∧ n < # bytes ∧ bytes2int(bytes) = 0 → bytes[n] = i2b(0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bytes2int(bytes) = 0, n < # bytes ⊦ bytes[n] = i2b(0), bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bytes = 0 ↔ bytes = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ 0 ≤ m;