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Proof step 2 from proof bytes2int-zero-05 (previous step)

bytes2int(bytes) = 0, n < # bytes ⊦ bytes[n] = i2b(0), bytes = []

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ bytes ≠ [] → (bytes2int(bytes) = 0 ↔ (∀ by. by ∈ bytes → b2i(by) = 0))
Proof step 4:
bytes ≠ [] → (bytes2int(bytes) = 0 ↔ (∀ by. by ∈ bytes → b2i(by) = 0)), bytes2int(bytes) = 0, n < # bytes ⊦ bytes[n] = i2b(0), bytes = []

Rule argument

name: bytes2int-zero-06 subst: [bytes] → [bytes]

Additional information

Used terms: bytes