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Proof step 2 from proof bytes2int-zero-06 (previous step)

⊦ bytes = [], bytes2int(bytes) = 0 ↔ (∀ by. by ∈ bytes → b2i(by) = 0)

User applied rule case distinction

And obtained the following new goals

Proof step 3:
bytes2int(bytes) = 0 ⊦ ∀ by. by ∈ bytes → b2i(by) = 0, bytes = []
Proof step 6:
∀ by. by ∈ bytes → b2i(by) = 0 ⊦ bytes2int(bytes) = 0, bytes = []

Rule argument

pos: right 2

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