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Proof step 3 from proof bytes2int-zero-06 (previous step)

bytes2int(bytes) = 0 ⊦ ∀ by. by ∈ bytes → b2i(by) = 0, bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
bytes2int(bytes) = 0, by ∈ bytes ⊦ bytes = [], b2i(by) = 0

Rule argument

Additional information