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Proof step 3 from proof fillsgn-len-short (previous step)

¬ # int2bytes(s2i(sho)) ≤ 2 ⊦ # fillsgn(2, int2bytes(s2i(sho))) = 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
2 < # int2bytes(s2i(sho)) ⊦ # fillsgn(2, int2bytes(s2i(sho))) = 2

Rule argument

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];% ⊦ # bytes = 0 ↔ bytes = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;