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Proof step 4 from proof fillsgn-len-short (previous step)

2 < # int2bytes(s2i(sho)) ⊦ # fillsgn(2, int2bytes(s2i(sho))) = 2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ 0 ≤ i ∧ int2bytes(i).first ≠ i2b(0) → (n < # int2bytes(i) ↔ 2 ^ (n→i(n) * 8) ≤ i)
Proof step 6:
¬(0 ≤ s2i(sho) ∧ int2bytes(s2i(sho)).first ≠ i2b(0)), 2 < # int2bytes(s2i(sho)) ⊦ # fillsgn(2, int2bytes(s2i(sho))) = 2

Rule argument

name: int2bytes-len-ls rotate: F subst: [i, n] → [s2i(sho), 2]

Additional information

Used simplifier rules: ⊦ ¬ 65536 ≤ s2i(sho); Used terms: s2i(sho), 2