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Proof step 8 from proof fix-bits2bytes (previous step)

# bits ≤ 8 * (n - 1) ⊦ bits = [], n = 0, fix(n, bits2bytes(bits)) = bits2bytes(fillsgn(n * 8, bits)), ¬ n ≤ # bits2bytes(bits) ∧ bits.first, ¬ n ≤ # bits2bytes(bits) ∧ ¬ bits.first

User applied rule cut formula

And obtained the following new goals

Proof step 9:
# bits ≤ 8 * (n - 1) ⊦ ¬ n ≤ # bits2bytes(bits), bits = [], n = 0, fix(n, bits2bytes(bits)) = bits2bytes(fillsgn(n * 8, bits)), ¬ n ≤ # bits2bytes(bits) ∧ bits.first, ¬ n ≤ # bits2bytes(bits) ∧ ¬ bits.first

Rule argument

fma: ¬ n ≤ # bits2bytes(bits)

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < n → n ≠ 0;% ⊦ m < n → (n ≤ m ↔ false); Used formulas: ¬ n ≤ # bits2bytes(bits)