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Proof step 9 from proof fix-bits2bytes (previous step)

# bits ≤ 8 * (n - 1) ⊦ ¬ n ≤ # bits2bytes(bits), bits = [], n = 0, fix(n, bits2bytes(bits)) = bits2bytes(fillsgn(n * 8, bits)), ¬ n ≤ # bits2bytes(bits) ∧ bits.first, ¬ n ≤ # bits2bytes(bits) ∧ ¬ bits.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
n ≤ # bits2bytes(bits), # bits ≤ 8 * (n - 1) ⊦ bits = [], n = 0, fix(n, bits2bytes(bits)) = bits2bytes(fillsgn(n * 8, bits))

Proof step 9 from proof fix-bits2bytes (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information