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Proof step 7 from proof getInt-theorem (previous step)

⊦ bor(b2i(by3) i<< 24, bor(band(b2i(by2), 255) i<< 16, bor(band(b2i(by1), 255) i<< 8, band(b2i(by0), 255)))) = bytes2int(by3 ' + by2 ' + by1 ' + by0 ')

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ bytes ≠ [] → bytes2int(bytes + by ') = bor(bytes2int(bytes) * 256, band(b2i(by), 255))
Proof step 9:
by3 ' + by2 ' + by1 ' ≠ [] ⊦ bor(b2i(by3) i<< 24, bor(band(b2i(by2), 255) i<< 16, bor(band(b2i(by1), 255) i<< 8, band(b2i(by0), 255)))) = bor(bytes2int(by3 ' + by2 ' + by1 ') * 256, band(b2i(by0), 255))

Rule argument

name: bytes2int-rec-bor rotate: F subst: [by, bytes] → [by0, by3 ' + by2 ' + by1 ']

Additional information

Used simplifier rules: ⊦ ¬ bytes + bytes0 ≠ [] ↔ bytes = [] ∧ bytes0 = [];% ⊦ by ' ≠ [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1; Used terms: by0, by3 ' + by2 ' + by1 '