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Proof step 9 from proof getInt-theorem (previous step)

by3 ' + by2 ' + by1 ' ≠ [] ⊦ bor(b2i(by3) i<< 24, bor(band(b2i(by2), 255) i<< 16, bor(band(b2i(by1), 255) i<< 8, band(b2i(by0), 255)))) = bor(bytes2int(by3 ' + by2 ' + by1 ') * 256, band(b2i(by0), 255))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
⊦ bor(b2i(by3) i<< 24, bor(band(b2i(by2), 255) i<< 16, bor(band(b2i(by1), 255) i<< 8, band(b2i(by0), 255)))) = bor(bytes2int(by3 ' + by2 ' + by1 ') * 256, band(b2i(by0), 255)), bor(b2i(by3) i<< 24, bor(band(b2i(by2), 255) i<< 16, band(b2i(by1), 255) i<< 8)) = bytes2int(by3 ' + by2 ' + by1 ') * 256

Rule argument

Additional information

Used simplifier rules: ⊦ bor(i, j) = bor(j, i);% ⊦ bor(bor(i, i0), j0) = bor(i, bor(i0, j0));% ⊦ bor(i, j) ≠ bor(i0, j) → i ≠ i0; (forward)% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by ' + bytes ≠ [];% ⊦ band(i, j) = band(j, i);