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Proof step 17 from proof int2bytes-butlast (previous step)

¬(i % 256 ≠ 0 ∧ i < 0), i < ~128, ~256 < i, i < 0 ⊦ (i - 255) / 256 = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
i % 256 = 0, i < ~128, ~256 < i, i < 0 ⊦ (i - 255) / 256 = ~1

Rule argument

Additional information

Used simplifier rules: ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;