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Proof step 15 from proof int2bytes-butlast (previous step)

i < ~128, ~256 < i, i < 0 ⊦ (i - 255) / 256 = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ i % 256 ≠ 0 ∧ i < 0 → (i - 255) / 256 = i / 256 - 1
Proof step 17:
¬(i % 256 ≠ 0 ∧ i < 0), i < ~128, ~256 < i, i < 0 ⊦ (i - 255) / 256 = ~1
Proof step 23:
i % 256 ≠ 0 ∧ i < 0, i < ~128, ~256 < i, i < 0 ⊦ i / 256 - 1 = ~1

Rule argument

seq: ⊦ i % 256 ≠ 0 ∧ i < 0 → (i - 255) / 256 = i / 256 - 1 subst: [i] → [i] rotate: F spec: int-div inst: name: div-minus255-256

Additional information

Used terms: i