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Proof step 23 from proof int2bytes-butlast (previous step)

i % 256 ≠ 0 ∧ i < 0, i < ~128, ~256 < i, i < 0 ⊦ i / 256 - 1 = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
i < ~128, ~256 < i, i < 0 ⊦ i % 256 = 0, i / 256 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i - j = i0 ↔ i = i0 + j;