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Proof step 7 from proof int2bytes-byte (previous step)

8 < # int2bits(i), i < 128, ~128 ≤ i ⊦ bits2bytes(int2bits(i)) = i2b(i) '

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: bits2bytes-rec seq: ⊦ 8 < # bits → bits2bytes(bits) = bits2bytes(firstn(# bits - 8, bits)) + i2b(bits2int(lastn(8, bits))) subst: [bits] → [int2bits(i)] flags: rewrite, current

Additional information

Used terms: int2bits(i)