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Proof step 9 from proof int2bytes-byte (previous step)

8 < # int2bits(i), 8 < # int2bits(i), i < 128, ~128 ≤ i ⊦ bits2bytes(firstn(# int2bits(i) - 8, int2bits(i))) + i2b(bits2int(lastn(8, int2bits(i)))) = i2b(i) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: Last: ⊦ bytes + by = bytes + by '; from specification list[bytelist]