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Proof step 3 from proof int2bytes-le127 (previous step)

0 ≤ i, i ≤ 127 ⊦ bits2bytes(int2bits(i)) = i2b(i) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ # bits ≤ 8 → bits2bytes(bits) = i2b(bits2int(bits)) '
Proof step 5:
¬ # int2bits(i) ≤ 8, 0 ≤ i, i ≤ 127 ⊦ bits2bytes(int2bits(i)) = i2b(i) '

Rule argument

name: bits2bytes-base rotate: F subst: [bits] → [int2bits(i)]

Additional information

Used simplifier rules: ⊦ bits2int(int2bits(i)) = i;% ⊦ by ' = by0 ' ↔ by = by0; Used terms: int2bits(i)