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Proof step 5 from proof int2bytes-le127 (previous step)

¬ # int2bits(i) ≤ 8, 0 ≤ i, i ≤ 127 ⊦ bits2bytes(int2bits(i)) = i2b(i) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
0 ≤ i, 8 < # int2bits(i), i ≤ 127 ⊦ bits2bytes(int2bits(i)) = i2b(i) '

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;