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Proof step 12 from proof int2bytes-len-def (previous step)

1 ≤ n, # int2bits(i) = m * 8 + n, n < 8 ⊦ m = (m * 8 + (n - 1)) / 8, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
# int2bits(i) = m * 8 + n, 1 ≤ n, n < 8 ⊦ n = 0, (n - 1) / 8 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward)%0 < n ⊦ (* n) ≤ m → m ≠ 0; (forward)% ⊦ m = m + n ↔ n = 0;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m * n = n * m;% ⊦ m0 * m * n = (m0 * m) * n;%n ≠ 0 ⊦ (n0 + m * n) / n = n0 / n + m;