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Proof step 10 from proof int2bytes-len-def (previous step)

# int2bits(i) = m * 8 + n, n < 8 ⊦ m = (m * 8 + n - 1) / 8, n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ n ≤ n0 → m + n0 - n = m + (n0 - n)
Proof step 12:
1 ≤ n, # int2bits(i) = m * 8 + n, n < 8 ⊦ m = (m * 8 + (n - 1)) / 8, n = 0

Rule argument

seq: ⊦ n ≤ n0 → m + n0 - n = m + (n0 - n) subst: [n, n0, m] → [1, n, m * 8] rotate: F spec: nat inst: name: add-03

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < 1 ↔ m = 0; Used terms: 1, n, m * 8