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Proof step 9 from proof int2bytes-len-def (previous step)

# int2bits(i) = m * 8 + n ∧ n < 8 ∧ 8 ≠ 0 ⊦ n = 0, m = (# int2bits(i) - 1) / 8

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
# int2bits(i) = m * 8 + n, n < 8 ⊦ m = (m * 8 + n - 1) / 8, n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)