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Proof step 16 from proof int2bytes-len-def (previous step)

# int2bits(i) = m * 8 + n ∧ n < 8 ∧ 8 ≠ 0, n = 0 ⊦ m = 1 + (# int2bits(i) - 1) / 8

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
# int2bits(i) = m * 8 ⊦ m = 1 + (m * 8 - 1) / 8

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ 0 + m = m;