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Proof step 17 from proof int2bytes-len-def (previous step)

# int2bits(i) = m * 8 ⊦ m = 1 + (m * 8 - 1) / 8

User applied rule cut formula

And obtained the following new goals

Proof step 18:
# int2bits(i) = m * 8 ⊦ m = 0, m = 1 + (m * 8 - 1) / 8

Rule argument

fma: m = 0

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ int2bits(j) ≠ []; Used formulas: m = 0