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Proof step 11 from proof int2bytes-len-le (previous step)

int2bytes(i) ≠ [], 2 ^ (n→i(# int2bytes(i).rest) * 8) ≤ bytes2int(int2bytes(i)), 0 ≤ i ⊦ int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
0 ≤ i, 2 ^ (n→i(# int2bytes(i).rest) * 8) ≤ i ⊦ int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)

Rule argument

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];%int2int: ⊦ bytes2int(int2bytes(i)) = i;