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Proof step 9 from proof int2bytes-len-le (previous step)

2 ^ (n→i(# int2bytes(i).rest) * 8) ≤ bytes2int(int2bytes(i).first ' + int2bytes(i).rest), 0 ≤ i ⊦ int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ bytes ≠ [] → bytes.first ' + bytes.rest = bytes
Proof step 11:
int2bytes(i) ≠ [], 2 ^ (n→i(# int2bytes(i).rest) * 8) ≤ bytes2int(int2bytes(i)), 0 ≤ i ⊦ int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)

Rule argument

seq: ⊦ bytes ≠ [] → bytes.first ' + bytes.rest = bytes subst: [bytes] → [int2bytes(i)] rotate: F spec: list inst: bytelist name: fr

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ []; Used terms: int2bytes(i)