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Proof step 5 from proof int2bytes-len-le (previous step)

0 ≤ i, ¬ b2i(int2bytes(i).first) ≤ 0 → 2 ^ (n→i(# int2bytes(i).rest) * 8) ≤ bytes2int(int2bytes(i).first ' + int2bytes(i).rest) ⊦ int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)

User applied rule case distinction

And obtained the following new goals

Proof step 6:
0 ≤ i ⊦ ¬ b2i(int2bytes(i).first) ≤ 0, int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)
Proof step 9:
2 ^ (n→i(# int2bytes(i).rest) * 8) ≤ bytes2int(int2bytes(i).first ' + int2bytes(i).rest), 0 ≤ i ⊦ int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)

Rule argument

pos: left 2

Proof step 5 from proof int2bytes-len-le (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information