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Proof step 19 from proof int2bytes-len-neg (previous step)

n→i(n0) = i + 1, j + 2 ^ ((i + 1) * 8 - 2) < 0, j + 2 ^ (8 * i) ≤ 0, 0 ≤ i, 2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1), j < 0, 0 ≤ 2 ^ ((i + 1) * 8 - 1) + j ⊦ n0 = i→n(i) + 1, n0 * 8 = 1, n0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 20:
n→i(n0) = i + 1, j + 2 ^ ((i + 1) * 8 - 2) < 0, j + 2 ^ (8 * i) ≤ 0, 0 ≤ i, 2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1), j < 0, 0 ≤ 2 ^ ((i + 1) * 8 - 1) + j ⊦ i + 1 < n→i(n0), n0 = i→n(i) + 1, n0 * 8 = 1, n0 = 0

Rule argument

fma: i + 1 < n→i(n0)

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i + j < i + i0 ↔ j < i0; Used formulas: i + 1 < n→i(n0)