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Proof step 20 from proof int2bytes-len-neg (previous step)

n→i(n0) = i + 1, j + 2 ^ ((i + 1) * 8 - 2) < 0, j + 2 ^ (8 * i) ≤ 0, 0 ≤ i, 2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1), j < 0, 0 ≤ 2 ^ ((i + 1) * 8 - 1) + j ⊦ i + 1 < n→i(n0), n0 = i→n(i) + 1, n0 * 8 = 1, n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
n→i(n0) = i + 1, 0 ≤ 2 ^ ((i + 1) * 8 - 1) + j, j < 0, 2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1), 0 ≤ i, j + 2 ^ (8 * i) ≤ 0, j + 2 ^ ((i + 1) * 8 - 2) < 0 ⊦ n0 = 0, n0 * 8 = 1, n0 = i→n(i) + 1

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ i;% ⊦ i + j ≤ i0 + j ↔ i ≤ i0;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i * j = j * i;