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Proof step 15 from proof int2bytes-len-one (previous step)

~128 ≤ i ∧ i < 128, i2b(i) ' = by ' ⊦ i = b2i(by)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
i < 128, ~128 ≤ i ⊦ i = b2i(i2b(i))

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ by ' = by0 ' ↔ by = by0;