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Proof step 16 from proof int2bytes-len-one (previous step)

i < 128, ~128 ≤ i ⊦ i = b2i(i2b(i))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i

Rule argument

seq: ⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i subst: [i] → [i] rotate: F spec: byte inst: name: bib-in-01

Additional information

Used simplifier rules: i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ ¬ i ≤ j ↔ j < i;%i + 1 = i0 ⊦ j < (* i0) → ¬ (* i) < j; Used terms: i