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Proof step 1 from proof int2bytes-minus-256 (conclusion)

⊦ int2bytes(~256) = i2b(~1) ' + i2b(0) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ int2bytes(i) = bits2bytes(int2bits(i))
Proof step 3:
⊦ bits2bytes(int2bits(~256)) = i2b(~1) ' + i2b(0) '

Rule argument

name: int2bytes rotate: F subst: [i] → [~256]

Additional information

Used terms: ~256