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Proof step 3 from proof int2bytes-minus-256 (previous step)

⊦ bits2bytes(int2bits(~256)) = i2b(~1) ' + i2b(0) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
i < 0 ⊦ int2bits((* i)) = sgn(bitsinvert(uint2bits(abs(i))) +1)
Proof step 5:
~256 < 0 ⊦ bits2bytes(sgn(bitsinvert(uint2bits(abs(~256))) +1)) = i2b(~1) ' + i2b(0) '

Rule argument

seq: i < 0 ⊦ int2bits((* i)) = sgn(bitsinvert(uint2bits(abs(i))) +1) subst: [i] → [~256] rotate: F spec: int2bits inst: name: int2bits-neg-num

Additional information

Used terms: ~256