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Proof step 1 from proof int2int (conclusion)

⊦ bytes2int(int2bytes(i)) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ int2bytes(i) = bits2bytes(int2bits(i))
Proof step 3:
⊦ bytes2int(bits2bytes(int2bits(i))) = i

Rule argument

name: int2bytes rotate: F subst: [i] → [i]

Additional information

Used terms: i