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Proof step 3 from proof int2int (previous step)

⊦ bytes2int(bits2bytes(int2bits(i))) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 5:
⊦ bits2int(bytes2bits(bits2bytes(int2bits(i)))) = i

Rule argument

name: bytes2int rotate: F subst: [bytes] → [bits2bytes(int2bits(i))]

Additional information

Used terms: bits2bytes(int2bits(i))