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Proof step 5 from proof int2int (previous step)

⊦ bits2int(bytes2bits(bits2bytes(int2bits(i)))) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ bits2int(sgn(bits)) = bits2int(bits)
Proof step 7:
⊦ bits2int(sgn(bytes2bits(bits2bytes(int2bits(i))))) = i

Rule argument

seq: ⊦ bits2int(sgn(bits)) = bits2int(bits) subst: [bits] → [bytes2bits(bits2bytes(int2bits(i)))] rotate: T spec: int2bits inst: name: bits2int-sgn

Additional information

Used terms: bytes2bits(bits2bytes(int2bits(i)))