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Proof step 7 from proof int2int (previous step)

⊦ bits2int(sgn(bytes2bits(bits2bytes(int2bits(i))))) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ bits ≠ [] → sgn(bytes2bits(bits2bytes(bits))) = sgn(bits)

Rule argument

name: bits2bits-sgn rotate: F subst: [bits] → [int2bits(i)]

Additional information

Used simplifier rules: ⊦ sgn(int2bits(i)) = int2bits(i);% ⊦ bits2int(int2bits(i)) = i;% ⊦ int2bits(j) ≠ []; Used terms: int2bits(i)